Solve Equation 18 for "R" Considering equation 19:
Rrog is a distance from a star in which resultant of gravity forces isotropically becomes zero, so Range of Gravity for Star with mass "M" surrounded by space with string density "ρ" is a better name!
"e" is vibrating energy of a single string located at the distance R' from the center of star with mass "M" and radius "R"
h = Planck constant
Rrog Simplified
Light is a gas of open strings and it blocks gravity, the reason Sunlight does not block its gravity is that the photons and gravitons are in the same direction. To block gravity light must travel in the opposite direction to gravitons.
Classical Gravity Correction
"Y" = Distance between the surface of two masses
"R" = Distance between center of two masses
"Rrog " = Gravity Range of the larger mass "M"
When two masses are tangent "Y = 0", we come up with Newtonian Gravity
If Space Density is absolute zero, ρ=0, then Newtonian Gravity governs the universe
"D" = Dimension which gravity takes effect which is probably one (D=1)